(x-1)(x-2)(x-4)(x-8)=7x^2

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Solution for (x-1)(x-2)(x-4)(x-8)=7x^2 equation: 



(x-1)(x-2)(x-4)(x-8)=7x^2

We move all terms to the left:

(x-1)(x-2)(x-4)(x-8)-(7x^2)=0

determiningTheFunctionDomain
-7x^2+(x-1)(x-2)(x-4)(x-8)=0

We multiply parentheses ..

-7x^2+(+x^2-2x-1x+2)(x-4)(x-8)=0

We multiply parentheses ..

-7x^2+(+x^2-2x-1x+2)(+x^2-8x-4x+32)=0

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